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Electron Gain Enthalpy: Trends Across a Period and Down a Group, with Exceptions

Study guide — Electron Gain Enthalpy: Trends Across a Period and Down a Group, with Exceptions
By Aniket Bhardwaj · 10 November 2026 · Updated 10 November 2026 · Inorganic Chemistry

Class 11 periodic-table questions often ask: “Why is the electron gain enthalpy of chlorine more negative than that of fluorine?” or “Which element has the most negative value?” These are favourite one-liners in board papers and entrance tests. This article gives a clean rule set, the exceptions, and a few numerical conversions that appear in problems.

Waterfall bars show sodium ionisation at +496 kJ mol⁻¹, chlorine electron gain at −349 kJ mol⁻¹, and the net endothermic change of +147 kJ mol⁻¹.
Chlorine’s electron gain only partly offsets the energy needed to ionise sodium.

What it means

Electron gain enthalpy (ΔegH) is the enthalpy change when a neutral gaseous atom accepts one electron to form a gaseous anion:

X(g) + e− → X−(g)    ΔegH (kJ mol−1)

The trends

DirectionGeneral trendReason
Across a period (left to right)Becomes more negativeIncreasing nuclear charge, decreasing size, so the added electron is held more strongly
Down a groupBecomes less negativeIncreasing atomic size; the added electron is farther from the nucleus
Group 17Most negative values in the tableOne electron short of a stable noble gas configuration
Noble gasesPositiveFull outer shell; extra electron must go into a new shell
Group 2 and group 15 (N)Less negative than expected (or positive)Full s-subshell (Be, Mg) or half-filled p-subshell (N) is stable

The big exception: fluorine versus chlorine

By the “down the group” rule, fluorine should be higher than chlorine. In fact the commonly quoted order is Cl > F > Br > I (most negative first). Fluorine’s 2p subshell is very small, so the added electron enters a crowded space and feels strong repulsion from the seven electrons already there. Chlorine’s larger 3p subshell has more room, so its extra electron is accepted more comfortably. A similar effect makes sulphur more negative than oxygen, and phosphorus more negative than nitrogen, in the usual textbook tables.

Worked examples

The values below are typical textbook figures used only for practice. If your question or textbook gives different numbers, use those.

Example 1: energy per atom in eV. Given ΔegH(Cl) = −349 kJ mol−1, find the energy released per atom in eV. (1 eV = 1.602 × 10−19 J; NA = 6.022 × 1023 mol−1.)

Energy per atom = 349 000 J mol−1 ÷ 6.022 × 1023 = 5.795 × 10−19 J.

In eV: 5.795 × 10−19 ÷ 1.602 × 10−19 = 3.62 eV released per chlorine atom.

Example 2: energy released by a given mass. How much energy is released when 1.00 g of gaseous chlorine atoms each gain one electron? Use ΔegH = −349 kJ mol−1.

Moles of Cl = 1.00 ÷ 35.45 = 0.02821 mol.

Energy = 0.02821 × 349 = 9.84 kJ released.

Example 3: why NaCl formation is not just “atoms to ions”. Given ionisation enthalpy of Na(g) = +496 kJ mol−1 and ΔegH of Cl(g) = −349 kJ mol−1, find the net enthalpy change for Na(g) + Cl(g) → Na+(g) + Cl−(g).

Net = +496 + (−349) = +147 kJ mol−1.

The step is endothermic, yet NaCl forms easily. The reason is the large energy released when the gaseous ions pack into a crystal, called lattice enthalpy. The electron gain enthalpy is therefore one term in a larger energy balance, not the whole story.

Example 4: choosing the right answer in an MCQ. Arrange F, Cl, Br in order of increasing negative value of ΔegH, using the order Cl > F > Br (largest negative first).

Increasing negative value means starting with the smallest: Br < F < Cl. Read the question carefully, because “increasing electron gain enthalpy” and “increasing negative value” are not always asked in the same way.

Common mistakes

  • Saying fluorine has the most negative value because it is “the most electronegative”. The usual textbook order puts chlorine first.
  • Mixing up “high electron gain enthalpy” with “large positive number”. A large negative number means a stronger tendency to gain an electron.
  • Applying the group trend to every element without checking exceptions such as N, Be, Mg and the noble gases.
  • Assuming the second electron gain enthalpy is also negative. For O− → O2− it is positive.
  • Forgetting to convert kJ mol−1 to J per atom (divide by NA) when asked for energy per atom.

Exam-relevance table

Question typeKey point
Why is Cl more negative than F?Small 2p subshell, strong electron–electron repulsion in F
Why do noble gases have positive values?Stable full shell, extra electron enters a higher shell
Why is N less negative than expected?Half-filled p3 configuration is stable
Unit conversionkJ mol−1 ÷ NA = J per atom; ÷ 1.602 × 10−19 = eV

Check your own textbook’s table of values and sign convention before you revise numbers.

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