Calculate force, kinetic energy, potential energy and work from whichever pairs of mass, acceleration, velocity, height, force and distance you know (g = 9.80665 m/s²).
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From the article Force, Work and Energy — The Formulas Connected Properly.
Question: A 5 kg box at rest is pushed by a constant horizontal force of 20 N across 4 m of frictionless floor. Find the acceleration, the work done and the final speed.
Acceleration: a = F/m = 20 ÷ 5 = 4 m/s²
Work: the force is along the motion, so θ = 0° and
cosθ = 1.
W = F s cosθ = 20 × 4 × 1 = 80 J
Final speed, route A (kinematics): v² = u² + 2as = 0 + 2(4)(4) = 32, so v = √32 = 5.657 m/s
Check, route B (work–energy theorem): the floor is frictionless, so
all 80 J becomes kinetic energy.
½mv² = 80 → ½(5)v² = 80 → 2.5 v² = 80 →
v² = 32 → v = 5.657 m/s. ✔
Two completely different chapters, the same answer. That is the chain working.
Worked in full in Force, Work and Energy — The Formulas Connected Properly.
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