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Class 11 p-Block — The Boron and Carbon Families

By Aniket Bhardwaj · 17 September 2026 · CBSE/ICSE Concept

Group 13 and Group 14 are where the Class 11 p-block chapter becomes real. Both groups begin with an element that refuses to behave like the rest of its family — boron and carbon — and both show a trend that reverses expectations halfway down. If you understand why each anomaly happens, you stop having to memorise a list of exceptions.

The two families at a glance

GroupMembersValence configurationMetallic character
13 — the boron familyB, Al, Ga, In, Tlns² np¹B is a non-metal (metalloid); Al, Ga, In, Tl are metals
14 — the carbon familyC, Si, Ge, Sn, Pbns² np²C is a non-metal; Si and Ge are metalloids; Sn and Pb are metals

In both groups metallic character increases down the group, because the outer electrons get further from the nucleus and are lost more easily.

Trend 1 — atomic radius does not increase smoothly

Approximate atomic radii for Group 13 (in picometres) run B ≈ 85, Al ≈ 143, Ga ≈ 135, In ≈ 167, Tl ≈ 170. Read that again: gallium is slightly smaller than aluminium, even though it is one period lower.

The reason is the ten 3d electrons that appear between aluminium and gallium. The d electrons shield the outer electrons from the nucleus poorly, so the effective nuclear charge felt by gallium's outer electron is higher than expected, and the atom is pulled in tighter. This "d-block contraction" argument is a standard reasoning question in the board exam.

Trend 2 — the inert pair effect

Down Groups 13 and 14, the lower oxidation state (+1 for Group 13, +2 for Group 14) becomes more stable, and the group oxidation state (+3, +4) becomes less stable.

The ns² pair of electrons becomes increasingly reluctant to take part in bonding, because the intervening d and f electrons shield the nucleus poorly and the ns pair is held more tightly. So:

Why boron is the odd one out

Boron is anomalous for three connected reasons: it is very small, it has a high ionisation enthalpy, and it has no d orbitals in its valence shell.

The three boron compounds you must know

Borax, Na₂B₄O₇·10H₂O. Its solution is alkaline because it hydrolyses:

Na₂B₄O₇ + 7H₂O → 2NaOH + 4H₃BO₃

On strong heating borax loses its water, swells and then melts to a clear glassy bead:

Na₂B₄O₇·10H₂O →(heat) Na₂B₄O₇ →(heat) 2NaBO₂ + B₂O₃

That bead dissolves coloured metal oxides to give characteristic colours — the borax bead test.

Orthoboric acid, H₃BO₃. It is a soft, white, soapy-feeling solid with a layered structure held together by hydrogen bonds. It is a weak monobasic Lewis acid — and the word monobasic is the trap. It does not donate any of its three protons directly. Instead it accepts an OH⁻ from water:

B(OH)₃ + 2H₂O ⇌ [B(OH)₄]⁻ + H₃O⁺

On heating it loses water in stages: H₃BO₃ →(about 370 K) HBO₂ (metaboric acid) →(red heat) B₂O₃ (boric anhydride).

Diborane, B₂H₆. It has only 12 valence electrons for what looks like eight bonds, so it is electron deficient. Four hydrogens lie in the plane in ordinary two-centre two-electron bonds; the other two are bridging hydrogens held by three-centre two-electron "banana" bonds, in which one pair of electrons is shared over B–H–B. It burns and hydrolyses readily:

B₂H₆ + 3O₂ → B₂O₃ + 3H₂O   ·   B₂H₆ + 6H₂O → 2H₃BO₃ + 6H₂

Aluminium is amphoteric

Aluminium dissolves in acid and in alkali, which is why aluminium vessels should not be used for either:

2Al + 6HCl → 2AlCl₃ + 3H₂
2Al + 2NaOH + 6H₂O → 2Na[Al(OH)₄] + 3H₂

Worked example 1 — molar mass of borax and boric acid

Atomic masses used: Na = 22.990, B = 10.81, O = 15.999, H = 1.008.

Borax, Na₂B₄O₇·10H₂O
Na: 2 × 22.990 = 45.980
B: 4 × 10.81 = 43.240
O (in B₄O₇): 7 × 15.999 = 111.993
Water of crystallisation: 10 × 18.015 = 180.150
Running total: 45.980 + 43.240 = 89.220; 89.220 + 111.993 = 201.213; 201.213 + 180.150 = 381.363
M(borax) = 381.363 ≈ 381.36 g/mol

Orthoboric acid, H₃BO₃
H: 3 × 1.008 = 3.024
B: 1 × 10.81 = 10.810
O: 3 × 15.999 = 47.997
M(H₃BO₃) = 3.024 + 10.810 + 47.997 = 61.831 ≈ 61.83 g/mol

Diborane, B₂H₆
B: 2 × 10.81 = 21.620; H: 6 × 1.008 = 6.048
M(B₂H₆) = 21.620 + 6.048 = 27.668 ≈ 27.67 g/mol

Worked example 2 — percentage of boron in borax

Mass of boron in one mole of borax = 43.240 g. Molar mass of borax = 381.363 g/mol.

% B = (43.240 ÷ 381.363) × 100

43.240 ÷ 381.363 = 0.11338
0.11338 × 100 = 11.34 % boron by mass

Follow-up: what mass of borax supplies 5.00 g of boron?

Mass of borax = 5.00 ÷ 0.11338 = 44.10 g

Check: 44.10 × 0.11338 = 5.000 g of boron. ✓

Group 14 — why carbon is different

Carbon shows the same three causes as boron (small size, high ionisation enthalpy, no d orbitals) but the consequences are different, and two of them dominate the whole of organic chemistry.

Allotropes of carbon, compared without a diagram

PropertyDiamondGraphiteFullerene C₆₀
Hybridisationsp³sp²sp² (slightly pyramidalised)
StructureThree-dimensional network, each C bonded to four others, C–C ≈ 154 pmFlat hexagonal layers about 340 pm apart, held by weak forcesClosed cage of 20 six-membered and 12 five-membered rings
Electrical conductionInsulator — all four electrons are in σ bondsConducts along the layers — the fourth electron is delocalisedPoor conductor as the pure solid
Hardness / useHardest known natural substance; abrasives, cutting toolsSoft and slippery; lubricant, electrodes, pencil leadMolecular solid, soluble in some organic solvents

Both diamond and graphite are pure carbon. The difference in properties comes entirely from how the atoms are joined — a point board examiners like to test with "why does graphite conduct but diamond does not?".

Two industrial gases worth knowing

Water gas (CO + H₂) is made by passing steam over red-hot coke: C + H₂O → CO + H₂. Producer gas (CO + N₂) is made by passing air over hot coke. Carbon monoxide itself is highly poisonous because it binds to haemoglobin far more strongly than oxygen does, so it must only ever be handled in a properly ventilated laboratory under supervision.

Mistakes students repeat every year

  • Calling H₃BO₃ tribasic. It is monobasic, and it is a Lewis acid — it accepts OH⁻ from water rather than donating H⁺.
  • Assuming atomic radius always rises down a group. Ga is smaller than Al because of poor shielding by the 3d electrons.
  • Saying BF₃ is a Brønsted acid. It has no proton to give. It is a Lewis acid, an electron-pair acceptor.
  • Writing B³⁺ or Al³⁺ compounds carelessly. Boron never forms a simple cation; its compounds are covalent.
  • Expecting SiO₂ to resemble CO₂. One is a gas of small molecules, the other a giant covalent solid, for the pπ–pπ reason above.
  • Giving +4 as the most stable state for lead. The inert pair effect makes Pb(II) the stable one.
  • Forgetting the ten waters in borax. Leaving out the ·10H₂O turns a 381.36 g/mol answer into a 201.21 g/mol answer.

Where this is examined

ExamTypical question
CBSE Class 11Reasoning questions on the inert pair effect and boron's anomaly; preparation and properties of borax, boric acid and diborane; CO₂ versus SiO₂
ISC / ICSE Class 11–12Group trends with explanation; amphoteric character of aluminium
NEET / JEEStructure of diborane, Lewis acid strength order of boron halides, stability of Sn²⁺ and Pb⁴⁺
Class 12 p-blockThe same inert pair reasoning carries forward to Groups 15–18

Always confirm the current syllabus for your board before you decide how deeply to revise a topic, since chapter coverage is revised from time to time.

Check the group trends yourself. The Interactive Periodic Table lets you click through B, Al, Ga, In and Tl — and then C, Si, Ge, Sn and Pb — and compare atomic number, atomic mass, electronic configuration and block for each. Reading the gallium anomaly off the table is far more convincing than reading it in a paragraph.

Open the Interactive Periodic Table →

Need structured help with Class 11 inorganic chemistry? ABC Chemistry runs Class 11–12 chemistry coaching at its Gurugram centre plus online classes across India — details at abcchemistry.in.