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Class 12 Biomolecules — The Structures Worth Knowing

By Aniket Bhardwaj · 18 September 2026 · CBSE/ICSE Concept

Biomolecules looks like a reading chapter, and that is exactly why students lose marks in it. The questions are precise: which sugar is reducing, which linkage joins starch, what survives denaturation, the difference between a nucleoside and a nucleotide. This guide takes the structures that actually get asked, states each one carefully in words and tables, and works the numerical checks that prove you have the formula right.

Carbohydrates — the classification you are graded on

ClassMeaningExamples
MonosaccharideCannot be hydrolysed to a simpler sugarGlucose, fructose, ribose, galactose
OligosaccharideGives 2–10 monosaccharide units on hydrolysisSucrose, maltose, lactose (all disaccharides)
PolysaccharideGives a large number of monosaccharide unitsStarch, cellulose, glycogen
Reducing sugarReduces Tollens' and Fehling's reagents — has a free aldehyde or ketone groupAll monosaccharides, plus maltose and lactose
Non-reducing sugarDoes not reduce those reagentsSucrose

Glucose — an aldohexose, described carbon by carbon

Glucose is C₆H₁₂O₆. Its open-chain structure is a straight six-carbon chain:

CHO – CHOH – CHOH – CHOH – CHOH – CH₂OH
CarbonGroupEvidence in the chapter
C1–CHO (aldehyde)Gives silver mirror with Tollens', red Cu₂O with Fehling's; oxidised to gluconic acid by mild bromine water
C2–C5–CHOH (four secondary alcohols)Forms a pentaacetate with acetic anhydride — proving five –OH groups in total
C6–CH₂OH (primary alcohol)With C1, gives saccharic acid on oxidation with nitric acid, showing both ends can be oxidised
ChainStraight, unbranchedOn prolonged heating with HI it gives n-hexane

Why the open chain is not the whole story. Glucose fails some standard aldehyde tests: it gives no reaction with sodium hydrogensulphite or ammonia, it does not form the expected Schiff's test result, and its pentaacetate does not react with hydroxylamine. These observations show that the aldehyde group is not freely available — glucose exists mostly as a six-membered pyranose ring, formed when the –OH on C5 adds across the C1 carbonyl.

Ring closure creates a new stereocentre at C1, giving two forms called α-D-glucose and β-D-glucose. In solution the two interconvert through the open-chain form, so the optical rotation of a freshly prepared solution changes until it settles at an equilibrium value. This is mutarotation: pure α-D-glucose starts at about +111°, pure β-D-glucose at about +19.2°, and both drift to the equilibrium value of about +52.5°.

Fructose, also C₆H₁₂O₆, is a ketohexose — the carbonyl is at C2, not C1 — and it closes into a five-membered furanose ring. Even though it is a ketone, fructose still reduces Tollens' and Fehling's reagents, because in alkaline solution it rearranges to an aldose. That single sentence answers a very common two-mark question.

Disaccharides — the linkage decides everything

SugarUnitsLinkageReducing?
Sucroseα-D-glucose + β-D-fructoseC1 of glucose to C2 of fructoseNo — both anomeric carbons are used up in the link
MaltoseTwo α-D-glucoseα-1,4 glycosidicYes — the second unit keeps a free anomeric carbon
Lactoseβ-D-galactose + β-D-glucoseβ-1,4 glycosidicYes

Invert sugar. Sucrose is dextrorotatory, about +66.5°. Hydrolysis gives an equimolar mixture of glucose (+52.5°) and fructose (−92.4°). The sign of the mixture flips to negative, which is why hydrolysed sucrose is called invert sugar.

Compute the rotation of the mixture. An equimolar mixture rotates by the average of the two values:

(+52.5) + (−92.4) = −39.9
−39.9 ÷ 2 = −19.95 ≈ −20°

Positive before hydrolysis, negative after — the inversion is a straightforward arithmetic consequence of fructose being much more strongly laevorotatory than glucose is dextrorotatory.

Polysaccharides — same monomer, different linkage

PolysaccharideMonomerLinkage and shapeRole
Starch — amyloseα-D-glucoseα-1,4 only; long unbranched coiled chain; water solublePlant food store; the fraction that gives the blue colour with iodine
Starch — amylopectinα-D-glucoseα-1,4 chain with α-1,6 branch points; water insolubleThe branched, major fraction of starch
Celluloseβ-D-glucoseβ-1,4 only; straight, rigid chains that pack into fibresPlant cell wall — structural, not food
Glycogenα-D-glucoseLike amylopectin but more highly branchedAnimal food store — "animal starch"

Starch and cellulose are built from the same sugar. The only difference is α versus β at the linking carbon — and that one difference is why humans can digest starch but not cellulose.

Worked example 1 — glucose, sucrose, and a hydrolysis cross-check

Atomic masses: C = 12.011, H = 1.008, O = 15.999.

Glucose, C₆H₁₂O₆
C: 6 × 12.011 = 72.066
H: 12 × 1.008 = 12.096
O: 6 × 15.999 = 95.994
M = 72.066 + 12.096 = 84.162; 84.162 + 95.994 = 180.156 ≈ 180.16 g/mol

Sucrose, C₁₂H₂₂O₁₁
C: 12 × 12.011 = 144.132
H: 22 × 1.008 = 22.176
O: 11 × 15.999 = 175.989
M = 144.132 + 22.176 = 166.308; 166.308 + 175.989 = 342.297 ≈ 342.30 g/mol

Cross-check using the hydrolysis reaction. One sucrose plus one water gives one glucose plus one fructose, and glucose and fructose have the same formula:

Left-hand side: 342.297 + 18.015 = 360.312
Right-hand side: 2 × 180.156 = 360.312 ✓

The two sides match exactly, which confirms both molar masses and the reaction stoichiometry at the same time.

Proteins — from one amino acid to four levels of structure

An α-amino acid carries both an amino group and a carboxyl group on the same carbon:

H₂N – CH(R) – COOH

There are 20 α-amino acids in proteins; about 10 of them cannot be made by the human body and must come from the diet, so they are called essential. In the solid state and in neutral solution an amino acid exists as a zwitterion, ⁺H₃N–CH(R)–COO⁻, which is why amino acids are high-melting, water-soluble solids rather than ordinary organic liquids. At the isoelectric point the zwitterion carries no net charge and does not migrate in an electric field.

Two amino acids join by losing a water molecule between the –COOH of one and the –NH₂ of the other. The resulting –CO–NH– link is the peptide bond.

LevelWhat it describesHeld together by
PrimaryThe exact sequence of amino acids in the chainPeptide (covalent) bonds
SecondaryLocal shape: the right-handed α-helix or the β-pleated sheetHydrogen bonds between C=O and N–H groups of the backbone
TertiaryThe overall three-dimensional folding of one chainHydrogen bonds, disulphide bridges, electrostatic attraction, van der Waals forces
QuaternaryHow two or more folded chains (subunits) assembleThe same non-covalent forces, acting between subunits

Denaturation — heating, or adding acid — destroys the secondary and tertiary structure while leaving the primary structure intact, so the protein loses its biological activity. Boiling an egg and curdling milk are the two standard examples.

Worked example 2 — a dipeptide, checked two ways

Glycine, C₂H₅NO₂ (R = H)
C: 2 × 12.011 = 24.022; H: 5 × 1.008 = 5.040; N: 14.007; O: 2 × 15.999 = 31.998
M = 24.022 + 5.040 = 29.062; + 14.007 = 43.069; + 31.998 = 75.067 ≈ 75.07 g/mol

Alanine, C₃H₇NO₂ (R = CH₃)
C: 3 × 12.011 = 36.033; H: 7 × 1.008 = 7.056; N: 14.007; O: 31.998
M = 36.033 + 7.056 = 43.089; + 14.007 = 57.096; + 31.998 = 89.094 ≈ 89.09 g/mol

Route 1 — subtract the water lost. Forming one peptide bond releases one H₂O:
75.067 + 89.094 = 164.161
164.161 − 18.015 = 146.146 g/mol

Route 2 — build the formula and add it up. The dipeptide glycylalanine is C₅H₁₀N₂O₃:
C: 5 × 12.011 = 60.055; H: 10 × 1.008 = 10.080; N: 2 × 14.007 = 28.014; O: 3 × 15.999 = 47.997
60.055 + 10.080 = 70.135; + 28.014 = 98.149; + 47.997 = 146.146 g/mol

Both routes give 146.146 g/mol. When two independent methods agree, the formula is right.

Enzymes and vitamins — the exam-relevant facts

Enzymes are biocatalysts, and almost all of them are proteins. They are extremely specific — one enzyme typically catalyses one reaction — and they work by lowering the activation energy of that reaction, so it proceeds far faster at body temperature than it otherwise would. Because they are proteins, they are destroyed by the same conditions that denature any protein.

Vitamins divide into two groups by solubility, and the grouping explains the storage behaviour:

GroupMembersStored in the body?Named deficiency disease (syllabus)
Fat-solubleA, D, E, KYes — stored in liver and fatty tissueA: night blindness / xerophthalmia · D: rickets and osteomalacia · K: increased blood-clotting time
Water-solubleB group and CNo — excreted, so a regular supply is neededB₁: beriberi · B₁₂: pernicious anaemia · C: scurvy

These deficiency links are syllabus content for a chemistry paper, not medical guidance. Nutrition and any supplement decision belongs to a qualified doctor, never to a textbook list.

Nucleic acids — get these two definitions exactly right

Nucleoside = nitrogenous base + pentose sugar
Nucleotide = nitrogenous base + pentose sugar + phosphate group
DNARNA
Sugar2-deoxy-D-riboseD-ribose
BasesAdenine, Guanine, Cytosine, ThymineAdenine, Guanine, Cytosine, Uracil
StrandsDouble helix, two complementary strandsUsually a single strand
FunctionStores and transmits hereditary informationMainly protein synthesis

Adenine and guanine are purines (two fused rings); cytosine, thymine and uracil are pyrimidines (one ring). In the double helix the bases pair specifically: A with T through two hydrogen bonds, G with C through three. Because G–C pairs have an extra hydrogen bond, a region rich in G and C is harder to separate — a fact worth remembering as the reason the pairing is not arbitrary.

Mistakes that lose marks in this chapter

  • Calling sucrose a reducing sugar. Both anomeric carbons are locked into the glycosidic bond, so there is no free carbonyl. Maltose and lactose are reducing.
  • Saying starch and cellulose have different monomers. Both are made of glucose. The difference is α-1,4 versus β-1,4 linkage.
  • Swapping nucleoside and nucleotide. The phosphate is what makes it a nucleotide.
  • Saying denaturation breaks peptide bonds. It destroys secondary and tertiary structure only; the primary sequence survives.
  • Writing that fructose does not reduce Fehling's solution. It does, because it isomerises to an aldose in alkaline medium.
  • Forgetting why the cyclic structure was proposed. The evidence is the set of aldehyde tests glucose fails, plus mutarotation.
  • Claiming all vitamins are stored in the body. Only the fat-soluble ones are.

Where biomolecules is examined

ExamTypical question
CBSE Class 12Why glucose does not give certain aldehyde tests; reducing vs non-reducing sugars; the four levels of protein structure; nucleoside vs nucleotide
ISC Class 12Structures of glucose and fructose; hydrolysis products of disaccharides; zwitterion and isoelectric point
NEETHigh-frequency factual questions on linkages, base pairing and vitamin deficiency
IIT-JAM / CUET-PGStereochemistry of sugars, optical rotation and peptide sequencing

Verify every formula in this chapter numerically. Type C6H12O6, C12H22O11, C2H5NO2 or C3H7NO2 into the Molar Mass & Composition calculator and check the values worked out above — then confirm the sucrose hydrolysis balance for yourself: sucrose plus water must equal two glucose units by mass.

Open the Molar Mass & Composition Calculator →

Revising the Class 12 organic chapters for boards? ABC Chemistry runs Class 11–12 chemistry coaching at its Gurugram centre and online classes across India — details at abcchemistry.in.