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ICSE Class 10 Acids, Bases and Salts — Quick Revision

By Aniket Bhardwaj · 31 August 2026 · ICSE Class 10 Chemistry

"Acids, Bases and Salts" is one of the chapters ICSE examiners return to again and again, because it connects definitions, ionic theory, the pH scale and a long list of preparation methods. This revision sheet puts all of it in one place — the definitions in the exact wording the paper expects, the pH calculations worked out, the salt types with real examples, and the preparation routes you must be able to name.

Definitions — know all three levels

Arrhenius definition (the one ICSE expects first): an acid is a substance which, when dissolved in water, produces hydrogen ions (H⁺) as the only positive ions. A base produces hydroxide ions (OH⁻) as the only negative ions in aqueous solution. A base soluble in water is called an alkali.

HCl + H₂O → H₃O⁺ + Cl⁻   (the H⁺ never exists alone — it attaches to water)
NaOH → Na⁺ + OH⁻

Bronsted–Lowry definition: an acid is a proton (H⁺) donor, a base is a proton acceptor. This explains why NH₃, which contains no OH group, is still a base: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻.

Lewis definition: an acid is an electron-pair acceptor, a base an electron-pair donor. This is the broadest of the three and covers species such as AlCl₃ and BF₃.

Two facts ICSE tests directly: a substance behaves as an acid only in the presence of water (dry HCl gas does not turn dry blue litmus red), and acids conduct electricity in aqueous solution because they furnish ions.

Strong and weak, concentrated and dilute

These two pairs are not the same thing, and confusing them is a classic lost mark.

TermWhat it describesExamples
Strong acidAlmost completely ionised in waterHCl, H₂SO₄, HNO₃
Weak acidOnly partly ionised in waterCH₃COOH, H₂CO₃, HCOOH
Strong base (alkali)Almost completely ionisedNaOH, KOH
Weak baseOnly partly ionisedNH₄OH, Ca(OH)₂, Mg(OH)₂
ConcentratedLarge amount of acid in a small amount of waterConcentrated CH₃COOH is still a weak acid
DiluteSmall amount of acid in a large amount of waterDilute HCl is still a strong acid

The pH scale

pH measures how acidic or alkaline a solution is on a scale from 0 to 14.

pH = − log₁₀ [H⁺]     pOH = − log₁₀ [OH⁻]
pH + pOH = 14  (at 25 °C)     [H⁺] × [OH⁻] = 1 × 10⁻¹⁴

pH below 7 is acidic, exactly 7 is neutral, above 7 is alkaline. The scale is logarithmic: a solution of pH 3 has ten times more H⁺ ions than one of pH 4, and a hundred times more than pH 5.

Example 1. A solution has [H⁺] = 1 × 10⁻³ mol L⁻¹. Find its pH.
pH = − log (10⁻³) = 3 — acidic.

Example 2. Find the pH of 0.01 M HCl.
HCl is a strong acid and gives one H⁺ per molecule, so [H⁺] = 0.01 = 10⁻² mol L⁻¹.
pH = − log (10⁻²) = 2.

Example 3. Find the pH of 0.001 M NaOH.
[OH⁻] = 10⁻³ mol L⁻¹ → pOH = 3
pH = 14 − 3 = 11 — alkaline.

Example 4. Rainwater has pH 5.6. Find [H⁺].
[H⁺] = 10−5.6 = 2.5 × 10⁻⁶ mol L⁻¹ — mildly acidic, because dissolved CO₂ forms carbonic acid.

Neutralisation

An acid and a base react to give a salt and water. Stripped to its ions, every neutralisation is the same single reaction:

Acid + Base → Salt + Water
H⁺(aq) + OH⁻(aq) → H₂O(l)   (the ionic equation, always exothermic)

Examples: NaOH + HCl → NaCl + H₂O; 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O; CuO + H₂SO₄ → CuSO₄ + H₂O.

Q. 25 mL of 0.1 M NaOH is exactly neutralised by 0.05 M HCl. What volume of acid is needed?

NaOH + HCl → NaCl + H₂O, so they react 1 : 1.

moles of NaOH = 0.1 × (25 ÷ 1000) = 0.0025 mol
moles of HCl required = 0.0025 mol
volume = 0.0025 ÷ 0.05 = 0.05 L = 50 mL

The answer makes sense: the acid is half as concentrated, so twice the volume is needed.

Types of salts

Salt typeDefinitionExamples
Normal saltAll replaceable hydrogen of the acid is replaced by a metal or ammonium ionNaCl, Na₂SO₄, KNO₃, CaCO₃
Acid saltOnly part of the replaceable hydrogen is replaced; formed from a polybasic acidNaHSO₄, NaHCO₃, Ca(HCO₃)₂
Basic saltFormed from partial neutralisation of a polyacidic base; still contains OH or OPb(OH)Cl, Zn(OH)Cl, basic copper carbonate
Double saltTwo simple salts crystallised together; ionises into all its ions in solutionPotash alum K₂SO₄·Al₂(SO₄)₃·24H₂O; Mohr's salt FeSO₄·(NH₄)₂SO₄·6H₂O
Complex saltContains a complex ion that does not break up in solutionSodium argentocyanide Na[Ag(CN)₂]; potassium ferrocyanide K₄[Fe(CN)₆]

The distinction between a double salt and a complex salt is a favourite question. A double salt gives the tests of all its component ions in solution; a complex salt does not, because the complex ion stays intact — a solution of Na[Ag(CN)₂] gives no test for ordinary Ag⁺ ions.

What kind of salt is it? — the acid–base parents rule

Made fromNature of the solutionExample
Strong acid + strong baseNeutral, pH ≈ 7NaCl, KNO₃
Strong acid + weak baseAcidic, pH < 7NH₄Cl, CuSO₄
Weak acid + strong baseAlkaline, pH > 7CH₃COONa, Na₂CO₃
Weak acid + weak baseClose to neutralCH₃COONH₄

Methods of preparing salts

  1. Direct combination of two elements — used for salts of metals with variable valency: 2Fe + 3Cl₂ → 2FeCl₃.
  2. Simple displacement — an active metal displaces hydrogen from a dilute acid: Zn + H₂SO₄ → ZnSO₄ + H₂.
  3. Precipitation (double decomposition) — used for insoluble salts: Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃.
  4. Neutralisation of an alkali by titration — used when both the base and the salt are soluble: NaOH + HCl → NaCl + H₂O.
  5. Neutralisation of an insoluble base or oxide — add excess solid to the warm acid, then filter off what did not dissolve: CuO + H₂SO₄ → CuSO₄ + H₂O.
  6. Action of a dilute acid on a carbonate or bicarbonate: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂; NaHCO₃ + HCl → NaCl + H₂O + CO₂.
  7. Oxidation of a metal by an oxidising acid — for example copper with concentrated nitric acid, where no hydrogen is released.

Choosing the right method is a standard exam question: if the salt is insoluble use precipitation; if it is soluble and the base is soluble use titration; if the salt is soluble but the base is insoluble use the excess-solid-and-filter method.

Water of crystallisation — three words to keep straight

TermMeaningExample
EfflorescenceA hydrated salt loses its water of crystallisation to the air and becomes powderyNa₂CO₃·10H₂O
DeliquescenceA solid absorbs so much moisture that it dissolves in it, forming a solutionCaCl₂, NaOH, MgCl₂
HygroscopyA substance absorbs moisture but does not dissolve in itConcentrated H₂SO₄, quicklime CaO

Common mistakes that cost marks

  • Saying "strong" when you mean "concentrated". Strength is about degree of ionisation; concentration is about how much water is present.
  • Forgetting that acids need water. Dry HCl gas has no free H⁺ ions and shows no acidic behaviour.
  • Writing pH as a unit-carrying quantity. pH is a pure number — it has no unit.
  • Assuming every salt solution is neutral. Only a strong-acid + strong-base salt is neutral; NH₄Cl solution is acidic and Na₂CO₃ solution is alkaline.
  • Calling every salt with hydrogen an acid salt. NaHSO₄ is an acid salt; NaOH-derived salts such as CH₃COONa contain hydrogen in the anion but are normal salts, because all the replaceable acidic hydrogen has been replaced.
  • Using titration for an insoluble salt. You cannot titrate to PbSO₄ — it precipitates immediately, so the precipitation method is the right one.

Practise pH calculations until they are instant. The free pH / pOH calculator converts between [H⁺], [OH⁻], pH and pOH in either direction — enter 0.001 M NaOH and see pH 11 appear, or enter pH 5.6 and get [H⁺] back, exactly as in the worked examples above.

Open the pH / pOH Calculator →

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