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Isotopes as Tracers in Science — Labelling, Isotope Dilution and Delta Notation

By Aniket Bhardwaj · 12 September 2026 · Formula & Research

Isotopes of an element have the same number of protons and electrons, so they behave almost identically in chemical reactions — but they have different masses, and some of them decay. That combination is quietly one of the most powerful tools in science: it lets you mark a particular atom, let it go through a reaction, a living body or a river system, and then find it again at the other end. This article covers the three calculations a tracer study actually uses — decay correction, isotope dilution and delta notation — and then the assumption that every tracer study depends on and that occasionally fails.

The formulas you already know

Decay:   N = N₀ e−λt     A = A₀ e−λt     λ = ln 2 / t½
Mass balance for a spike:   xsns + xxnx = xm(ns + nx)
Delta notation:   δ = [ (Rsample / Rstandard) − 1 ] × 1000 ‰

What each term means

SymbolMeaningUnit
N, N₀Number of radioactive nuclei now and at t = 0count (or mol)
A, A₀Activity — disintegrations per second — now and at t = 0Bq (1 Bq = 1 s⁻¹); MBq is common in practice
λDecay constant, fixed for a given nuclides⁻¹, h⁻¹ or yr⁻¹
xAtom fraction of the tracer isotope in a material (spike s, unknown sample x, mixture m)dimensionless (or atom %)
nAmount of the element in each portionmol
RRatio of a heavy isotope to a light one, e.g. ¹³C/¹²Cdimensionless
δDeviation of a sample's ratio from a reference material, in parts per thousand‰ (per mil)

Two families of tracer exist and they answer different questions. Stable isotopes (²H, ¹³C, ¹⁵N, ¹⁸O) are detected by mass — they never disappear, so they suit long studies and anything involving people or food. Radioactive tracers are detected by their emissions, which makes them exquisitely sensitive at tiny chemical amounts, but the clock is always running and they carry handling, licensing and disposal obligations.

Worked example 1 — decay correction for a radiotracer

A short-lived nuclide with t½ = 6.01 h is prepared with an activity of 740 MBq. What activity remains 4.00 hours later?

λ = ln 2 ÷ t½ = 0.69315 ÷ 6.01 = 0.11533 h⁻¹
λt = 0.11533 × 4.00 = 0.46132
e−0.46132 = 0.6305
A = 740 × 0.6305 = 467 MBq, i.e. 63.1% remains

Sanity check: 4.00 h is two-thirds of one half-life, so the answer must lie between 100% and 50%, closer to 50%. 63% ✔ It is also worth noting that the answer would be 56.2% after 5 h and exactly 50% at 6.01 h — the correction matters over a working morning, which is why every activity in this kind of work is quoted with a calibration time.

Worked example 2 — isotope dilution, the trick that beats calibration curves

An unknown amount of a carbon-containing compound has the natural ¹³C atom fraction, xx = 0.0110. To it is added a spike of 1.00 × 10⁻⁵ mol of the same compound enriched to xs = 0.990 in ¹³C. After complete mixing, the mixture measures xm = 0.250. How much of the compound was present?

Mass balance on ¹³C atoms:
0.990 ns + 0.0110 nx = 0.250 (ns + nx)
ns(0.990 − 0.250) = nx(0.250 − 0.0110)
0.740 ns = 0.2390 nx
nx = ns × 0.740 ÷ 0.2390 = ns × 3.0962
nx = 1.00 × 10⁻⁵ × 3.0962 = 3.10 × 10⁻⁵ mol

Verify by substitution: total ¹³C = 0.990(1.00 × 10⁻⁵) + 0.0110(3.0962 × 10⁻⁵) = 9.900 × 10⁻⁶ + 3.406 × 10⁻⁷ = 1.0241 × 10⁻⁵ mol. Total carbon-bearing amount = 4.0962 × 10⁻⁵ mol. Ratio = 1.0241 ÷ 4.0962 = 0.2500 ✔

Now see why this method is prized. The answer came from a ratio, not from an absolute signal. Once the spike has mixed completely, you may lose material during extraction, clean-up and injection; the instrument may drift; the recovery may be 40%. None of it matters, because losses remove both isotopes in the same proportion and the ratio survives. That is why isotope dilution is treated as one of the highest-accuracy approaches in analytical chemistry, and why the same reasoning appears in biology as the "dilution of a known dose" method for measuring a volume you cannot see into.

Worked example 3 — delta notation

A carbon sample gives Rsample = 0.0112057 for ¹³C/¹²C. Taking the reference material's ratio as Rstandard = 0.0112372 for this exercise, find δ¹³C.

Rstandard − Rsample = 0.0112372 − 0.0112057 = 3.15 × 10⁻⁵
3.15 × 10⁻⁵ ÷ 0.0112372 = 2.8031 × 10⁻³
Rsample/Rstandard = 1 − 0.0028031 = 0.9971969
δ¹³C = (0.9971969 − 1) × 1000 = −2.80 ‰

A negative δ means the sample is depleted in the heavy isotope relative to the standard. Differences at this level are far too small to see in a molar mass, which is why δ values are reported in parts per thousand — the interesting variation in nature lives in the fourth and fifth decimal place of a ratio.

Where this is actually used

FieldWhat the tracer reveals
Reaction mechanismLabelling one specific oxygen or carbon shows which bond broke. The classic teaching case is ester hydrolysis, where ¹⁸O in the alcohol product distinguishes acyl–oxygen from alkyl–oxygen cleavage
Metabolism and nutritionA ¹³C- or ²H-labelled nutrient is followed through the body and its breakdown products identified, without any radiation dose
Drug developmentLabelled compounds map where a drug goes, what it is converted into and how it leaves the body
Medical imaging and therapyShort-lived radionuclides attached to a targeting molecule reveal function rather than anatomy
Hydrology and climate archives²H and ¹⁸O in water vary with evaporation, altitude and temperature, so water can be traced back to where it fell
Environmental forensicsIsotopic composition can distinguish sources of a pollutant, or link a contaminant to a specific process
Food authenticityPlants using different photosynthetic pathways fix carbon with different isotopic signatures, so added sugar or origin claims can be tested
Analytical standardsIsotope dilution mass spectrometry as a reference method for certifying the concentration of a substance

Radiometric dating uses the same decay law but answers a different question — the age of a sample rather than the path of an atom — and it is covered separately in half-life and radiocarbon dating.

Where the simple treatment stops being valid

  • The tracer assumption is an approximation, not a law. "Isotopes behave identically" is very nearly true for heavy elements and roughly true for ¹³C and ¹⁵N. It is not true for hydrogen: deuterium is twice the mass of protium, and a C–D bond breaks measurably more slowly than a C–H bond. That kinetic isotope effect is a nuisance if you wanted a passive label — and a deliberate experiment if you wanted to know whether the C–H bond breaks in the rate-determining step.
  • Labels on exchangeable positions scramble. A ²H or ³H placed on an O–H, N–H or S–H group, or alpha to a carbonyl, can swap with solvent protons within minutes. The label must sit on a carbon that does not exchange, or the experiment measures the solvent.
  • Radioactive decay tracks the nuclide, never the molecule. A count tells you where the atom is, not what compound it is in. If the labelled molecule is metabolised, the signal follows the fragments. Any quantitative claim about the parent compound needs a separation step before counting.
  • Isotope dilution fails if the spike does not equilibrate. The whole method rests on the spike and the sample becoming chemically indistinguishable before any loss occurs. Add the spike after an extraction, or to a sample where the analyte is bound in a different chemical form, and the result is confidently wrong. Add the spike as early as possible — that is the entire discipline of the technique.
  • Natural abundance is not zero. The unknown in Example 2 already contained 1.10% ¹³C, and leaving that term out would have changed the answer. Every enrichment calculation must correct for natural background.
  • δ is a relative number, not a concentration. Two samples can have identical δ¹³C and completely different carbon contents. δ values are also meaningless without naming the reference material they were measured against.
  • Detection limits and background matter. At very low enrichment, the measured difference approaches instrument noise; at very low activity, natural background counts dominate. Both set a floor on what a tracer study can honestly claim.
  • Radioactive work is regulated work. Handling, shielding, licensing, waste disposal and dose limits are governed by the applicable regulatory authority. Nothing in this article is a procedure — check the current official rules and your institution's approvals before any work with radionuclides.

Why this matters for JAM, GATE, NET and CUET-PG

Exam areaWhat is typically asked
Nuclear chemistryDecay law, decay constant and half-life; activity after a given time; decay-mode identification
Analytical chemistryIsotope dilution mass balance; why a ratio method resists recovery loss
Reaction mechanismIsotopic labelling to distinguish mechanisms; primary versus secondary kinetic isotope effect
Atomic structureIsotopes, mass number, and why atomic masses are weighted averages of isotopic masses
SpectroscopyIsotope patterns in mass spectra; M+1 and M+2 peaks

Every radiotracer question starts with λ = ln 2 / t½. The Half-Life calculator links half-life, decay constant, elapsed time and the fraction remaining, so you can check the decay correction in Example 1 and any activity-versus-time problem.

Open the Half-Life Calculator →

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