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JAM Physical Chemistry — The Most Scoring Units and How to Drill Them

By Aniket Bhardwaj · 29 August 2026 · IIT-JAM Chemistry

"Scoring" is a word thrown around loosely in exam preparation, usually meaning "a topic someone told me is important". A more useful definition, and the one used here, is this: a scoring unit is one where a correct method reliably produces a correct answer, where the question cannot easily be made ambiguous, and where you can verify your own work without a solution key. By that definition, physical chemistry is the most scoring subject in IIT-JAM Chemistry, and within it some units are more dependable than others.

No honest article can tell you what percentage of the paper comes from a given unit — that varies year to year and nobody outside the organising institute knows it in advance. What can be said with confidence is which units are structurally reliable, and that is what follows.

Tier one, unit 1 — Gaseous state

Small syllabus, closed-form results, and heavily represented in numerical-answer questions. You need the ideal gas equation, Dalton's law of partial pressures, Graham's law of effusion, the kinetic theory expressions for molecular speeds, the Maxwell–Boltzmann distribution qualitatively, real gases and the van der Waals equation, compressibility factor, and critical constants.

PV = nRT  ·  (P + a/Vm²)(Vm − b) = RT  ·  Z = PVm/RT
urms = √(3RT/M)  ·  uavg = √(8RT/πM)  ·  ump = √(2RT/M)

Here P is pressure, V molar or total volume, n moles, T absolute temperature, M the molar mass in kg mol⁻¹ (not g mol⁻¹ — this is the most common unit slip in the whole unit), a and b the van der Waals constants. The three speeds are always in the ratio √2 : √(8/π) : √3 = 1.414 : 1.596 : 1.732, so ump < uavg < urms always, which is a free check on any answer.

Worked example 1 — ideal gas. Find the pressure exerted by 2.00 g of helium (M = 4.003 g mol⁻¹) in a 5.00 L vessel at 300 K.

n = 2.00 / 4.003 = 0.4996 mol

P = nRT/V = (0.4996 × 0.08206 × 300) / 5.00 = 12.300 / 5.00 = 2.46 atm

Worked example 2 — real gas correction. Compare the ideal and van der Waals pressures for 1.00 mol of CO₂ in 1.00 L at 300 K, given a = 3.640 L² atm mol⁻² and b = 0.04267 L mol⁻¹.

Ideal: P = RT/Vm = (0.08206 × 300) / 1.00 = 24.62 atm

van der Waals: P = RT/(Vm − b) − a/Vm²
= 24.618 / (1.00 − 0.04267) − 3.640 / (1.00)²
= 24.618 / 0.95733 − 3.640 = 25.716 − 3.640 = 22.08 atm

The real pressure is lower because at this density the attractive term dominates the excluded-volume term. Z = 22.08 / 24.62 = 0.897, less than 1 — consistent.

Tier one, unit 2 — Thermodynamics

The largest of the reliable units and the one that connects to everything else. Cover the first law and its application to reversible and irreversible processes, enthalpy and thermochemistry (Hess's law, Kirchhoff's equation), the second law and entropy, free energy and the criteria of spontaneity, and the Gibbs–Helmholtz and Clausius–Clapeyron relations.

Worked example 3 — isothermal reversible expansion. One mole of an ideal gas expands reversibly and isothermally at 300 K from 1.00 L to 10.0 L. Find w, q, ΔU and ΔSsystem.

w = −nRT ln(V₂/V₁) = −(1)(8.314)(300)(ln 10) = −(2494.2)(2.3026) = −5743 J = −5.74 kJ

ΔU = 0 for an isothermal ideal-gas process, so q = −w = +5.74 kJ

ΔSsystem = nR ln(V₂/V₁) = (8.314)(2.3026) = +19.14 J K⁻¹

Because the process is reversible, ΔSsurroundings = −19.14 J K⁻¹ and ΔSuniverse = 0. That last equality is the definition of reversibility, and JAM tests it as a concept question at least as often as it tests the arithmetic.

Tier one, unit 3 — Solutions and colligative properties

Raoult's law, ideal and non-ideal solutions, relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, osmotic pressure, and the van't Hoff factor for electrolytes and for associating solutes. Every one of these is a one-formula-one-answer question type. The van't Hoff factor is the only real subtlety: i is greater than 1 for dissociation, less than 1 for association such as carboxylic acid dimerisation in benzene.

Tier one, unit 4 — Ionic equilibrium

pH of strong and weak acids and bases, buffers, hydrolysis of salts, solubility product and the common-ion effect, and indicator selection for titrations.

pH = −log[H⁺]  ·  pH = pKa + log([A⁻]/[HA])  ·  [H⁺] = √(Ka · C) for a weak acid

Tier two: reliable, but needing more setup

Chemical kinetics is as computable as thermodynamics, but requires you to determine the order before any formula applies, which adds a decision step. Electrochemistry is highly formula-driven but needs correct half-cell bookkeeping. Atomic structure and quantum chemistry gives beautifully clean numerical questions on hydrogen-like systems and node counting, alongside conceptual questions that require genuine understanding of the postulates.

How to actually drill a unit

Reading a chapter is not drilling. This four-pass method is:

PassWhat you doWhat it builds
1 — DeriveDerive each formula once from its starting point, on paperYou stop confusing similar-looking formulas because you know where each came from
2 — ComputeTen straightforward substitution problems, timed, no calculator shortcutsArithmetic speed and unit discipline
3 — InvertProblems that give you the answer and ask for an inputAlgebraic flexibility, which is what NAT questions really test
4 — MixProblems from this unit shuffled with three older units, unlabelledRecognition — the skill the exam actually measures

Pass 4 is the one candidates skip and the one that matters most. In the exam, no question arrives with a chapter heading attached.

The unit and setup errors that cost the most marks

  • Molar mass in g mol⁻¹ inside a speed formula. urms = √(3RT/M) needs M in kg mol⁻¹ when R is 8.314 J K⁻¹ mol⁻¹. For N₂ at 300 K: √(3 × 8.314 × 300 / 0.028014) = √267 103 = 517 m s⁻¹. Using 28.014 instead gives 16.3 m s⁻¹, which should immediately look wrong — molecules do not amble.
  • Mixing values of R. Use 0.08206 L atm K⁻¹ mol⁻¹ with pressures in atm and volumes in litres; use 8.314 J K⁻¹ mol⁻¹ for energy. Never both in one expression.
  • Sign of work. With the convention ΔU = q + w, expansion by the system gives negative w. Half of all wrong first-law answers are sign errors, not method errors.
  • Forgetting the van't Hoff factor. A 0.1 m NaCl solution depresses the freezing point roughly twice as much as 0.1 m glucose. Colligative properties count particles, not formula units.
  • Using [H⁺] = √(KaC) for a strong acid, or for a weak acid so dilute that the approximation breaks down. Check that the calculated dissociation is small before trusting the shortcut.

Drill gas-law numericals with instant verification. The Ideal Gas Law calculator solves for any of P, V, n or T, handles unit conversion, and shows the substitution — so when your hand answer disagrees you can see immediately whether the fault was the method or the arithmetic.

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