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Spectroscopy in Art Conservation and Forensic Analysis

By Aniket Bhardwaj · 29 September 2026 · Formula & Research

A conservator examining a centuries-old painting and a forensic analyst examining a questioned document are asking the same underlying chemical question: what exact substance is this, and can I find out without destroying it? Spectroscopy answers that question by reading how a material absorbs or scatters light, and it does so non-destructively, which is precisely why it dominates both fields. This article works through the two calculations that sit behind almost every spectroscopic identification — absorbance from Beer–Lambert's law, and converting between wavelength and wavenumber — and then shows honestly what these techniques can and cannot tell you.

The formulas

Beer–Lambert law: A = ε l c

Wavenumber: ṽ (cm⁻¹) = 1 / λ (cm)     equivalently     ṽ (cm⁻¹) = 107 / λ (nm)

What each term means

TermMeaningUnit
AAbsorbance — how much light of a given wavelength the sample absorbsdimensionless
εMolar absorptivity — how strongly the specific substance absorbs at that wavelengthL mol⁻¹ cm⁻¹
lPath length light travels through the samplecm
cConcentration of the absorbing speciesmol/L
ṽWavenumber — spacing between vibrational or rotational energy levels, the native unit of FTIR and Raman spectracm⁻¹
λWavelengthnm or cm

Worked example 1 — quantifying a pigment by absorbance

A microscopic paint-chip sample is dissolved and placed in a 1.00 cm cuvette. At its characteristic absorption maximum the solution reads A = 0.612, and the pigment's molar absorptivity at that wavelength is known to be ε = 8 400 L mol⁻¹ cm⁻¹. Find the concentration.

Rearranging A = ε l c: c = A ÷ (ε × l)

c = 0.612 ÷ (8 400 × 1.00) = 0.612 ÷ 8 400

c = 7.29 × 10⁻⁵ mol/L

This is exactly the same algebra used in a school laboratory to find the concentration of an unknown solution — the identity of the sample changes, the mathematics does not.

Worked example 2 — reading an FTIR band

An infrared spectrum shows a strong absorption band at λ = 5.75 μm. Convert this to wavenumber and identify what kind of bond it represents.

Convert μm to cm: 5.75 μm = 5.75 × 10⁻⁴ cm

ṽ = 1 ÷ λ = 1 ÷ (5.75 × 10⁻⁴) = 1 739 cm⁻¹

A sharp, strong band close to 1 700–1 750 cm⁻¹ is the textbook signature of a carbonyl (C=O) stretch — found in esters, aldehydes, ketones and many binding media (oils, resins) used historically in paint and varnish.

FTIR spectra are almost always reported directly in wavenumber, not wavelength, because wavenumber is linearly proportional to vibrational energy — equally spaced peaks on a wavenumber axis correspond to equally spaced energy levels, which a wavelength axis does not give.

Where this is actually used

In art conservation, Fourier-transform infrared (FTIR) spectroscopy and Raman spectroscopy identify the binding medium and varnish of a painting (oil, tempera, natural resin, synthetic polymer) from its characteristic vibrational fingerprint, without removing more than a microscopic sample — or, with portable Raman instruments, without touching the artwork at all. X-ray fluorescence (XRF) is used the same way to identify the elemental composition of pigments: a painting genuinely from an earlier century should not contain pigments that were not chemically available until later. Titanium white, for instance, only became a common artists' pigment in the twentieth century, so its presence in paint claimed to be centuries older than that is a material fact worth investigating — spectroscopy establishes the chemistry, and separately, art historians and conservators weigh what that chemistry means for attribution.

In forensic science, the same instruments examine questioned documents. FTIR and Raman spectra of ink from different pens on the same document can reveal whether all the writing was made with the same ink formulation, and UV–visible microspectrophotometry compares the absorbance spectra of fibres or dyes recovered from a crime scene against reference samples. Because these techniques need only a few micrograms of sample and leave the evidence physically intact, they are preferred wherever the sample itself must be preserved for further testing or presented later.

Common mistakes that cost marks

  • Confusing wavelength and wavenumber. They are inversely related, not directly proportional — a larger wavenumber corresponds to a smaller wavelength and a higher energy. Students often instinctively treat the two as if they move together.
  • Applying Beer–Lambert to an opaque or strongly scattering sample. The law assumes simple transmission through a clear solution. A solid paint flake or a fibre scatters light and needs diffuse-reflectance or ATR (attenuated total reflectance) techniques, whose signal does not follow the same simple linear form as A = εlc.
  • Treating a spectroscopic match as absolute proof. A spectrum identifies the chemical composition of a material — it tells you an ink or pigment is consistent (or inconsistent) with a given formulation. It does not, by itself, date the object or prove authorship; those conclusions require combining the chemistry with historical, documentary or other physical evidence.
  • Forgetting units before converting. Path length in Beer–Lambert must be in centimetres and wavenumber conversions must use consistent length units throughout — a wavelength left in nanometres while ε is quoted per centimetre is a common source of order-of-magnitude errors.

Exam relevance

ExamTypical use
IIT-JAM / CUET-PG Physical ChemistryBeer–Lambert numericals, IR/Raman selection rules, wavelength–wavenumber conversions
GATE ChemistrySpectroscopic techniques, functional group identification from IR data
CSIR-NET Physical ChemistryVibrational and electronic spectroscopy, instrumentation principles

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