Why Is Water Polar? Bonding, Geometry and Consequences
"Why is water polar?" looks like a one-line question, and students answer it in one line — "because oxygen is more electronegative than hydrogen". That answer is only half a mark. The full answer needs two conditions, and the second one is where most marks are lost. This article gives the complete reasoning, the numbers to quote, and the consequences that examiners love to ask about.
Polarity needs two things, not one
A molecule is polar only if both of these are true:
- The individual bonds are polar (there is an electronegativity difference).
- The molecular shape does not cancel those bond dipoles out.
Carbon dioxide proves why the second condition matters. C=O bonds are strongly polar, yet CO₂ has a dipole moment of zero. Its shape is linear, O=C=O at 180°, so the two bond dipoles point in exactly opposite directions and cancel completely. Same kind of polar bond, opposite answer — because of geometry.
Condition 1 — the O–H bond is polar
On the Pauling scale, oxygen has an electronegativity of 3.44 and hydrogen 2.20.
As a rough working guide used in school and entrance syllabi: ΔEN below about 0.4 gives an essentially non-polar covalent bond, roughly 0.4 to 1.7 is polar covalent, and above about 1.7 the bond has strong ionic character. A difference of 1.24 puts O–H firmly in the polar covalent range. The shared electron pair sits closer to oxygen, so oxygen carries a partial negative charge (δ−) and each hydrogen carries a partial positive charge (δ+).
Condition 2 — the shape is bent, so nothing cancels
Oxygen in water has six valence electrons. Two of them are used in bonding pairs with the hydrogens, and the remaining four sit as two lone pairs. That gives four electron domains around oxygen, so by VSEPR the electron-pair geometry is tetrahedral. But we name the molecular shape from the atoms only, and only three atoms are present — so the shape is bent (angular), classified as AX₂E₂.
Picture it without a diagram: put the oxygen at the centre. The two hydrogens go down and outwards, like the two arms of the letter V. The two lone pairs point up and backwards, into the empty space above the V. Lone pairs occupy more room than bonding pairs, so they squeeze the two O–H bonds together: the ideal tetrahedral angle of 109.5° is compressed to the measured 104.5°.
Because the molecule is bent, the two O–H bond dipoles do not oppose each other. They add up along the bisector of the H–O–H angle, pointing from the midpoint of the two hydrogens towards the oxygen. The lone pairs reinforce the same direction. The result is a real, measurable net dipole.
Putting a number on it
Two bond dipoles of magnitude μbond separated by an angle θ add like vectors:
Check this against the real value. The measured dipole moment of a water molecule in the gas phase is 1.85 D. With θ = 104.5°:
θ ÷ 2 = 52.25°, and cos 52.25° = 0.6124
μbond = 1.85 ÷ (2 × 0.6124) = 1.85 ÷ 1.2248 = 1.51 D
An O–H bond dipole of about 1.5 D is exactly what is expected from an electronegativity difference of 1.24. The vector model and the experiment agree.
Now test the same formula on CO₂. Here θ = 180°, so θ ÷ 2 = 90° and cos 90° = 0.
μnet = 2 × μbond × 0 = 0 D
The molecule is non-polar despite two strongly polar bonds. One formula, both answers — which is why geometry must be part of your explanation.
Consequence 1 — an absurdly high boiling point
Because one end of the molecule is δ+ hydrogen and the other end carries lone pairs on a small, highly electronegative oxygen, water molecules form hydrogen bonds with each other. Each molecule can form up to four: two through its own hydrogens, two through its two lone pairs.
Compare water with the other hydrides of its group, which have no significant hydrogen bonding:
| Molecule | Molar mass (g/mol) | Boiling point |
|---|---|---|
| H₂O | 18.02 | 100 °C |
| H₂S | 34.08 | about −60 °C |
| H₂Se | 80.98 | about −41 °C |
| H₂Te | 129.6 | about −2 °C |
Read that table carefully: from H₂S downwards the boiling point rises steadily with molar mass, exactly as dispersion forces predict. Water, the lightest of the four, should boil lowest of all — somewhere below −70 °C. It boils at 100 °C instead. That gap of well over 150 degrees is the price of breaking hydrogen bonds, and it exists only because water is polar with hydrogen attached to a small electronegative atom.
Individually a hydrogen bond in water is worth roughly 20 kJ/mol, against about 463 kJ/mol for the O–H covalent bond itself. A hydrogen bond is weak — but there are enormous numbers of them, and that is what boiling has to overcome.
Consequence 2 — water dissolves ionic and polar substances
When NaCl is placed in water, the δ− oxygen ends turn towards Na⁺ ions and the δ+ hydrogen ends turn towards Cl⁻ ions. Each ion is surrounded by a shell of oriented water molecules — this is hydration, and the energy released by it is what pays for pulling the crystal lattice apart.
Water also has an unusually high dielectric constant, about 78 at 25 °C, compared with around 2 for a non-polar solvent such as hexane. A high dielectric constant means the electrostatic attraction between separated Na⁺ and Cl⁻ is reduced dramatically inside water, so the ions stay apart instead of snapping back together. This is the quantitative reason behind the familiar rule "like dissolves like". Oil does not dissolve because it is non-polar: breaking water's hydrogen-bond network to make room for it costs energy that nothing repays.
Consequence 3 — ice floats
In liquid water the hydrogen bonds constantly break and re-form, so molecules can pack reasonably close. On freezing, each molecule locks into four hydrogen bonds in a fixed tetrahedral arrangement, and that arrangement contains open hexagonal channels. The solid is therefore less dense than the liquid, which is why ice floats and why lakes freeze from the top. Almost every other substance is denser as a solid. The bent, polar shape of one small molecule is the whole reason.
Common mistakes that cost marks
- Stopping at electronegativity. "O is more electronegative than H" only explains the bond. You must add "and the molecule is bent, so the bond dipoles do not cancel" to earn the full mark.
- Calling the shape tetrahedral. The electron-pair geometry is tetrahedral; the molecular shape is bent. Shape is named from atoms only.
- Writing the bond angle as 109.5°. It is 104.5° in water, compressed by lone-pair repulsion. (In NH₃, with one lone pair, it is 107°.)
- Confusing hydrogen bonding with a covalent H bond. A hydrogen bond is an intermolecular attraction, roughly twenty times weaker than the O–H bond inside the molecule. Never write that boiling water breaks O–H bonds.
- Saying "water is polar because it has lone pairs". Lone pairs affect the shape and add to the dipole, but a polar bond is still required — CH₄ has no lone pairs and is non-polar; CCl₄ has polar bonds, no lone pairs on carbon, and is also non-polar because it is symmetrical.
Where this appears in exams
| Exam | Typical question |
|---|---|
| CBSE / ICSE Class 11 | VSEPR shape of H₂O, explain the 104.5° angle |
| CBSE / ICSE Class 12 | Hydrogen bonding, solubility and boiling-point trends |
| JEE / NEET | Predict polar vs non-polar (CO₂, BF₃, NH₃, CCl₄, H₂O) |
| IIT-JAM / CUET-PG | Dipole moment vector addition, dielectric constant and solvation |
| GATE / CSIR-NET | Solvent effects on reaction rate and mechanism, hydration energy |
Check the electronegativity values yourself. The Interactive Periodic Table gives the Pauling electronegativity, atomic radius and electron configuration for all 118 elements — so you can work out ΔEN for any bond in a question instead of guessing from memory.
Open the Interactive Periodic Table →Struggling with bonding and VSEPR? ABC Chemistry teaches Class 11–12 chemistry at the Gurugram coaching centre and through online classes across India, with home tuition available in Delhi-NCR — details at abcchemistry.in.