Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
Three boys A, B, C were asked to divide a certain number by 1001 by the method of factors. They took the factors in the orders 13, 11, 7; 7, 11, 13 and 11, 7, 13 respectively. If the first boy obtained 3, 2, 1 as successive remainders, then find the successive remainders obtained by the other two boys B and C.
Answer
Answer (as printed):
Explanation
13 x 11 y – 3 \ z = 7 × 1 + 1 = 8, 7 z–2 y = 11 z + 2 = 11 × 8 + 2 = 90; 1 – 1 x = 13 y + 3 = 13 × 90 + 3 = 1173. Now, 7 1173 11 167 – 4 So, B obtained 4, 2 and 2 as successive remainders. 13 15 – 2 1–2 And, 11 1173 7 106 – 7 C obtained 7, 1 and 2 as successive remainders. 13 15 – 1 1–2 NUMBER SYSTEM 13
Explanation as extracted from the printed page; notation may be imperfect.