Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
If $x, y, z$ and $w$ be the digits of a number beginning from the left, the number is
(a)xyzw
(b)wzyx
(c)$x+10 y+100 z+1000 w$
(d)$10^{3} x+10^{2} y+10 z+w$
Answer
Answer (as printed): D
Explanation
Let the thousand’s, hundred’s, ten’s and one’s digits be x, y, z, w respectively. Then, the number is 1000 x + 100 y + 10 z + w = 103 x + 102 y + 10 z + w.
Explanation as extracted from the printed page; notation may be imperfect.