ABC26GN0185 · Number System

Subject: General Aptitude · Chapter: Number System · Exam: 2008 · Marks: · Difficulty:

$(999)^{2}-(998)^{2}=$ ?

(a)1992

(b)1995

(c)1997

(d)1998

Answer

Answer (as printed): C

Explanation

$(999)^{2}-(998)^{2}=(999+998)(999-998)=(1997 \times 1)=1997$.

Explanation as extracted from the printed page; notation may be imperfect.

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