ABC26GN0200 · Number System

Subject: General Aptitude · Chapter: Number System · Exam: 2005 · Marks: · Difficulty:

If $a+b+c=0,(a+b)(b+c)(c+a)$ equals

(a)$a b(a+b)$

(b)$(a+b+c)^{2}$

(c)$-a b c$

(d)$a^{2}+b^{2}+c^{2}$

Answer

Answer (as printed): C

Explanation

$$\begin{aligned} a+b+c=0 & \Rightarrow a+b=-c,(b+c)=-a \text { and }(c+a)=-b \\ & \Rightarrow(a+b)(b+c)(c+a)=(-c) \times \\ & (-a) \times(-b)=-(a b c) . \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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