Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
$B$ takes the value
(a)0
(b)5
(c)9
(d)0 or 9
Answer
Answer (as printed): C
Explanation
It is given that $D=0$. So, we have $A=5$. So, 1 is carried over. $$1+B+C=10+C \Rightarrow 1+B=10 \Rightarrow B=9 .$$ Now, $1+C+C=A \Rightarrow 1+2 C=5 \Rightarrow 2 C=4 \Rightarrow C=2$. Hence $B=9$. $$\begin{aligned} & \text { (1) } \mathbb{C} \\ & C B A=5 \\ + & C C A=5 \\ \hline & \overline{A C} O \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.