Subject: General Aptitude · Chapter: Number System · Exam: 2006 · Marks: · Difficulty:
A 3-digit number $4 a 3$ is added to another 3-digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then, $(a+b)$ is
(a)10
(b)11
(c)12
(d)15
Answer
Answer (as printed): A
Explanation
Since $13 b 7$ is divisible by 11, we have $$(7+3)-(b+1)=0 \Rightarrow 9-b=0 \Rightarrow b=9 .$$ Putting $b=9, \mathrm{a}+8=9$ we get $a=1$. Hence, $(a+b)$ $=(1+9)=10$. $$\begin{array}{r} 4 a 3 \\ 984 \\ \hline 13 b 7 \\ \hline \end{array}$$
Explanation as extracted from the printed page; notation may be imperfect.