Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2007 · Marks: · Difficulty:
Find the largest number of five digits which, when divided by 16, 24, 30 or 36, leaves the same remainder 10 in each case.
Answer
Answer (as printed):
Explanation
Largest number of 5 digits = 99999. L.C.M. of 16, 24, 30 and 36 = 720. On dividing 99999 by 720, remainder obtained is 639. \ Largest number of 5 digits divisible by 16, 24, 30 and 36 = (99999 – 639) = 99360. Hence, required number = (99360 + 10) = 99370.
Explanation as extracted from the printed page; notation may be imperfect.