Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2006 · Marks: · Difficulty:
The least number of square tiles required to pave the ceiling of a room 15 m 17 cm long and 9 m 2 cm broad is
(a)656
(b)738
(c)814
(d)902
Answer
Answer (as printed): D
Explanation
For the least number of tiles, the size of the tile must be the maximum. Maximum size of the tile = H.C.F. of 1517 cm and 902 $\mathrm{cm}=41 \mathrm{cm}$. Hence, required number of tiles $$=\frac{\text { Area of ceiling }}{\text { Area of each tile }}=\left(\frac{1517 \times 902}{41 \times 41}\right)=814 .$$