Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:
The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is
(a)8739
(b)9831
(c)9834
(d)9893
Answer
Answer (as printed): B
Explanation
Greatest number of 4 digits is 9999. L.C.M. of 4, 7 and 13 = 364. On dividing 9999 by 364, the remainder obtained is 171. ∴ Greatest number of 4 digits divisible by 4, 7 and 13 $=(9999-171)=9828$. Hence, required number $=(9828+3)=9831$.
Explanation as extracted from the printed page; notation may be imperfect.