Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:
The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is
(a)840
(b)842
(c)2520
(d)2522
Answer
Answer (as printed): D
Explanation
L.C.M. of 4, 5, 6, 7 and 8 is 840. Let the required number be $840 k+2$, which is a multiple of 13. Least value of $k$ for which $(840 k+2)$ is divisible by 13 is $k=3$. $\therefore \quad$ Required number $=840 \times 3+2=2522$.
Explanation as extracted from the printed page; notation may be imperfect.