ABC26GN0717 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: 2005 · Marks: · Difficulty:

The value of $(0 . \overline{2}+0 . \overline{3}+0 . \overline{32})$ is
(a)$0 . \overline{77}$
(b)$0 . \overline{82}$
(c)$0 . \overline{86}$
(d)$0 . \overline{87}$
Answer
Answer (as printed): D
Explanation
$0 . \overline{2}+0 . \overline{3}+0 . \overline{32}=\left(\frac{2}{9}+\frac{3}{9}+\frac{32}{99}\right)=\left(\frac{22+33+32}{99}\right)=\frac{87}{99}=0 . \overline{87}$.

Explanation as extracted from the printed page; notation may be imperfect.

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