ABC26GN0875 · Simplification

Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:

An executive goes on a business trip. His daily schedule has a definite pattern. If he is busy with a meeting in the morning, he is free in the afternoon. When he returns, he realises that he attended 15 meetings altogether. There were 12 free mornings and 13 free afternoons. What was the duration of his trip?
Answer
Answer (as printed):
Explanation
Let M and A represent the number of busy mornings and busy afternoons respectively. Then, total number of mornings in the trip = 12 + M. And, total number of afternoons in the trip = 13 + A. Clearly, 12 + M = 13 + A or M – A = 1 ...(i) Total number of meetings = M + A So, M + A = 15 ...(ii) Adding (i) and (ii), we get: 2M = 16 or M = 8. Hence, duration of the trip = (12 + 8) = 20 days.

Explanation as extracted from the printed page; notation may be imperfect.

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