ABC26GN0903 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: 2006 · Marks: · Difficulty:
Given that $\left(1^{2}+2^{2}+3^{2}+\ldots . .+10^{2}\right)=385$, the value of $\left(2^{2}+4^{2}+6^{2}+\ldots . .+20^{2}\right)$ is equal to
(a)770
(b)1155
(c)1540
(d)$(385)^{2}$
Answer
Explanation
$$\begin{aligned} \left(2^{2}+4^{2}+6^{2}+\ldots+20^{2}\right) & =2^{2}\left(1^{2}+2^{2}+3^{2}+\ldots+10^{2}\right) \\ & =4 \times 385=1540 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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