ABC26GN0966 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:
If $\frac{x}{y}=\frac{6}{5}$, then the value of $\left(\frac{6}{7}-\frac{5 x-y}{5 x+y}\right)$ is equal to
(a)$\frac{1}{7}$
(b)$\frac{2}{7}$
(c)$\frac{3}{7}$
(d)$\frac{4}{7}$
Answer
Explanation
$$\begin{aligned} \left(\frac{6}{7}-\frac{5 x-y}{5 x+y}\right) & =\frac{6}{7}-\left(\frac{5 \frac{x}{y}-1}{5 \frac{x}{y}+1}\right)=\frac{6}{7}-\left(\frac{5 \times \frac{6}{5}-1}{5 \times \frac{6}{5}+1}\right) \\ & =\frac{6}{7}-\left(\frac{6-1}{6+1}\right)=\frac{6}{7}-\frac{5}{7}=\frac{1}{7} \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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