ABC26GN0968 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:
If $\frac{x}{2 y}=\frac{6}{7}$, the value of $\frac{x-y}{x+y}+\frac{14}{19}$ is
(a)$\frac{13}{19}$
(b)$\frac{15}{19}$
(c)1
(d)$1 \frac{1}{19}$
Answer
Explanation
$$\begin{aligned} & \frac{x}{2 y}=\frac{6}{7} \Rightarrow \frac{x}{y}=\left(2 \times \frac{6}{7}\right)=\frac{12}{7} . \\ & \therefore \quad \frac{x-y}{x+y}+\frac{14}{19}=\frac{\frac{x}{y}-1}{\frac{x}{y}+1}+\frac{14}{19}=\frac{\frac{12}{7}-1}{\frac{12}{7}+1}+\frac{14}{19}=\frac{(5 / 7)}{(19 / 7)}+\frac{14}{19} \\ & \quad=\left(\frac{5}{7} \times \frac{7}{19}\right)+\frac{14}{19}=\frac{5}{19}+\frac{14}{19}=\frac{19}{19}=1 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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