ABC26GN0994 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:
The expression $\frac{x+y}{x-y} \div \frac{(x+y)^{2}}{\left(x^{2}-y^{2}\right)}$ is equal to
(a)- 1
(b)$x-y$
(c)1
(d)$x+y$
Answer
Explanation
$\frac{x+y}{x-y} \div \frac{(x+y)^{2}}{x^{2}-y^{2}}=\frac{x+y}{x-y} \times \frac{\left(x^{2}-y^{2}\right)}{(x+y)^{2}}$ $$=\frac{\left(x^{2}-y^{2}\right)}{(x-y)(x+y)}=\frac{\left(x^{2}-y^{2}\right)}{\left(x^{2}-y^{2}\right)}=1 .$$
Explanation as extracted from the printed page; notation may be imperfect.
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