If a+b+c=2 s, then the value of (s-a)²+(s-b)² +(s-c)²+s² will be · ABC26GN0997

$(s-a)^{2}+(s-b)^{2}+(s-c)^{2}+s^{2}$ $$\begin{aligned} & =\left(s^{2}+a^{2}-2 s a\right)+\left(s^{2}+b^{2}-2 s b\right)+\left(s^{2}+c^{2}-2 s c\right)+s^{2} \\ & =4 s^{2}+\left(a^{2}+b^{2}+c^{2}\right)-2 s(a+b+c) \\ & =(2 s)^{2}+\left(a^{2}+b^{2}+c^{2}\right)-(a+b+c)(a+b+c) \\ & =(a+b+c)^{2}+\left(a^{2}+b^{2}+c^{2}\right)-(a+b+c)^{2} \\ & =a^{2}+b^{2}+c^{2} . \end{aligned}$$