ABC26GN0999 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:
If $a+b=2 c$, then the value of $\frac{a}{a-c}+\frac{b}{b-c}$ is
(a)$\frac{1}{2}$
(b)1
(c)2
(d)3
Answer
Explanation
$a+b=2 c \Rightarrow a=2 c-b$. $$\begin{aligned} \therefore \frac{a}{a-c}+\frac{b}{b-c} & =\frac{2 c-b}{(2 c-b)-c}+\frac{b}{(b-c)}=\frac{2 c-b}{c-b}+\frac{b}{b-c} \\ & =\frac{b-2 c}{b-c}+\frac{b}{b-c}=\frac{b-2 c+b}{b-c}=\frac{2(b-c)}{b-c}=2 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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