ABC26GN1013 · Simplification

Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:

$a$ is greater than $b$ by 2 and $b$ is greater than $c$ by 10. If $a+b+c=130$, then $(b+c)-a=$?

(a)34

(b)38

(c)42

(d)44

(e)None of these

Answer

Answer (as printed):

Explanation

$a=b+2 \Rightarrow b=a-2$. And, $b=c+10 \Rightarrow c=b-10=(a-2)-10=a-12$. $a+b+c=130 \Rightarrow a+(a-2)+(a-12)=130 \Rightarrow 3a=144 \Rightarrow a=48$. $\therefore (b+c)-a=[(a-2)+(a-12)]-a=(2a-14)-a=(a-14)=48-14=34$.

Explanation as extracted from the printed page; notation may be imperfect.

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