ABC26GN1224 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:
$(32)^{3}+(79)^{3}-(111)^{3}+3 \times 32 \times 79 \times 111$ is equal to
Answer
Explanation
Let $a=32, b=79, c=-111$. Then, $a+b+c=0$. So, $a^{3}+b^{3}+c^{3}=3 a b c \Rightarrow(32)^{3}+(79)^{3}-(111)^{3}$ $$=3 \times 32 \times 79 \times(-111)$$ $\therefore \quad$ Given exp. $=-(3 \times 32 \times 79 \times 111)+3 \times 32 \times 79$ $\times 111=0$.
Explanation as extracted from the printed page; notation may be imperfect.
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