Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: · Marks: · Difficulty:
What will come in place of the question mark in each of the following? (i) $\sqrt{\frac{32.4}{x}}=2$ (ii) $\sqrt{86.49}+\sqrt{5+(?)^2}=12.3$
Answer
Answer (as printed):
Explanation
(i) Let $\sqrt{\frac{32.4}{x}}=2$. Then $\frac{32.4}{x}=4 \Leftrightarrow 4x=32.4 \Leftrightarrow x=8.1$.
(ii) Let $\sqrt{86.49}+\sqrt{5+x^2}=12.3$. Then $9.3+\sqrt{5+x^2}=12.3 \Leftrightarrow \sqrt{5+x^2}=12.3-9.3=3 \Leftrightarrow 5+x^2=9 \Leftrightarrow x^2=9-5=4 \Leftrightarrow x=\sqrt{4}=2$.
Explanation as extracted from the printed page; notation may be imperfect.