ABC26GN1325 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: · Marks: · Difficulty:

If x =   and y =   , find the value of (x2 + y2).  5 – 3  5+ 3 ( 5 + 3) ( 5 + 3) ( 5 + 3)2 5 + 3 + 2 15

Answer

Answer (as printed):

Explanation

x = × = = = 4 + 15. ( 5 − 3) ( 5 + 3) (5 − 3) 2 ( 5 − 3) ( 5 − 3) ( 5 − 3)2 5 + 3 − 2 15 y= × = = = 4 − 15. ( 5 + 3) ( 5 − 3) (5 − 3) 2 2 2 2 2 \ x2 + y2 = (4 + 15) + (4 − 15) = 2 [(4) + ( 15) ] = 2 × 31 = 62.

Explanation as extracted from the printed page; notation may be imperfect.

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