ABC26GN1399 · Square Roots and Cube Roots
Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: 2003 · Marks: · Difficulty:
The approximate value of $\frac{3 \sqrt{12}}{2 \sqrt{28}} \div \frac{2 \sqrt{21}}{\sqrt{98}}$ is
(a)1.0605
(b)1.0727
(c)1.6007
(d)1.6026
Answer
Explanation
Given $\exp .=\frac{3 \sqrt{12}}{2 \sqrt{28}} \times \frac{\sqrt{98}}{2 \sqrt{21}}=\frac{3 \sqrt{4 \times 3}}{2 \sqrt{4 \times 7}} \times \frac{\sqrt{49 \times 2}}{2 \sqrt{21}}$ $$\begin{aligned} & =\frac{6 \sqrt{3}}{4 \sqrt{7}} \times \frac{7 \sqrt{2}}{2 \sqrt{21}}=\frac{21 \sqrt{6}}{4 \sqrt{7 \times 21}}=\frac{21 \sqrt{6}}{28 \sqrt{3}} \\ & =\frac{3}{4} \sqrt{2}=\frac{3}{4} \times 1.414=3 \times 0.3535=1.0605 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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