The square root of ((0.75)³)/(1-0.75)+ [0.75+(0.75)²+1] is · ABC26GN1413
Subject: General Aptitude · Chapter: Square Roots and Cube Roots
The square root of $\frac{(0.75)^{3}}{1-0.75}+\left[0.75+(0.75)^{2}+1\right]$ is
Answer
Explanation
$$\begin{aligned} \sqrt{\frac{(0.75)^{3}}{(1-0.75)}} & +\left[0.75+(0.75)^{2}+1\right] \\ & =\sqrt{\frac{(0.75)^{3}+(1-0.75)\left[(1)^{2}+(0.75)^{2}+1 \times 0.75\right]}{1-0.75}} \\ & =\sqrt{\frac{(0.75)^{3}+\left[(1)^{3}-(0.75)^{3}\right]}{1-0.75}} \\ & =\sqrt{\frac{1}{0.25}}=\sqrt{\frac{100}{25}}=\sqrt{4}=2 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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