ABC26GN1443 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: · Marks: · Difficulty:

If $\sqrt{2}=1.414$, the square root of $\frac{\sqrt{2}-1}{\sqrt{2}+1}$ is nearest to
(a)0.172
(b)0.414
(c)0.586
(d)1.414
Answer
Answer (as printed): B
Explanation
$\frac{\sqrt{2}-1}{\sqrt{2}+1}=\frac{(\sqrt{2}-1)}{(\sqrt{2}+1)} \times \frac{(\sqrt{2}-1)}{(\sqrt{2}-1)}=(\sqrt{2}-1)^{2}$. $$\therefore \quad \sqrt{\frac{\sqrt{2}-1}{\sqrt{2}+1}}=(\sqrt{2}-1)=(1.414-1)=0.414 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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