√(10+2 √(6)+2 √(10)+2 √(15)) is equal to · ABC26GN1494

Given $\sqrt{10+2 \sqrt{6}+2 \sqrt{10}+2 \sqrt{15}}$ $$\begin{aligned} & =\sqrt{10+2 \times \sqrt{3} \times \sqrt{2}+2 \times \sqrt{2} \times \sqrt{5}+2 \times \sqrt{3} \times \sqrt{5}} \\ & =\sqrt{2+3+5+2 \times \sqrt{2} \times \sqrt{3}+2 \times \sqrt{5} \times \sqrt{2}+2 \times \sqrt{5} \times \sqrt{3}} \\ & =\sqrt{(\sqrt{2})^{2}+(\sqrt{3})^{2}+(\sqrt{5})^{2}+2 \times \sqrt{2} \times \sqrt{3}+2 \times \sqrt{5} \times \sqrt{2}+2 \times \sqrt{5} \times \sqrt{3}} \\ & \quad \quad\left\{\because a^{2}+b^{2}+c^{2}+2 a b+2 b c+2 c a=(a+b+c)^{2}\right\} \\ & =\sqrt{(\sqrt{2}+\sqrt{3}+\sqrt{5})^{2}} \\ & =(\sqrt{2}+\sqrt{3}+\sqrt{5}) \end{aligned}$$