Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2011 · Marks: · Difficulty:
The sum of two numbers is 184. If one-third of the one exceeds one-seventh of the other by 8, find the smaller number.
Answer
Answer (as printed):
Explanation
Let the numbers be $x$ and $(184-x)$. Then, $\frac{x}{3}-\frac{(184-x)}{7}=8 \Rightarrow 7x-3(184-x)=168 \Rightarrow 10x=720 \Rightarrow x=72$. So, the numbers are 72 and 112. Hence, smaller number $=72$.
Explanation as extracted from the printed page; notation may be imperfect.