Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2008 · Marks: · Difficulty:
The product of two consecutive numbers is 4032. Find the numbers.
Answer
Answer (as printed):
Explanation
Let the numbers be $x$ and $(x+1)$. Then, $x(x+1)=4032 \Rightarrow x^{2}+x-4032=0 \Rightarrow x^{2}+64x-63x-4032=0 \Rightarrow x(x+64)-63(x+64)=0 \Rightarrow (x+64)(x-63)=0 \Rightarrow x=63$. $[\because x \neq -64]$ Hence, the required numbers are 63 and 64.
Explanation as extracted from the printed page; notation may be imperfect.