Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2005 · Marks: · Difficulty:
The ratio between a two-digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit’s place is 3 more than the digit in the ten’s place, what is the number?
Answer
Answer (as printed):
Explanation
Let the ten's digit be $x$. Then, unit's digit $=(x+3)$. Sum of the digits $=x+(x+3)=2x+3$. Number $=10x+(x+3)=11x+3$. $\therefore \frac{11x+3}{2x+3}=\frac{4}{1} \Leftrightarrow 11x+3=4(2x+3) \Leftrightarrow 3x=9 \Leftrightarrow x=3$. Hence, required number $=11x+3=36$.
Explanation as extracted from the printed page; notation may be imperfect.