A two-digit number is 7 times the sum of its two digits. The number that is formed by reversing its digits is… · ABC26GN1732

Let the ten's digit be $x$ and the unit's digit be $y$. Then, number $=10 x+y$. $$\therefore \quad 10 x+y=7(x+y) \Leftrightarrow 3 x=6 y \Leftrightarrow x=2 y .$$ Number formed by reversing the digits $=10 y+x$. $$\begin{aligned} & \therefore \quad(10 x+y)-(10 y+x)=18 \Leftrightarrow 9 x-9 y=18 \Leftrightarrow x-y \\ & =2 \Leftrightarrow 2 y-y=2 \Leftrightarrow y=2 . \end{aligned}$$ So, $x=2 y=4$. Hence, required number $=10 x+y=40+2=42$.