Subject: General Aptitude · Chapter: Problems on Numbers · Exam: · Marks: · Difficulty:
If 1 is added to the denominator of a fraction, the fraction becomes $\frac{1}{2}$. If 1 is added to the numerator of the fraction, the fraction becomes 1. The fraction is
(a)$\frac{1}{3}$
(b)$\frac{2}{3}$
(c)$\frac{3}{4}$
(d)$\frac{3}{2}$
Answer
Answer (as printed): B
Explanation
Let the fraction be $\frac{x}{y}$. Then, $$\frac{x}{y+1}=\frac{1}{2} \Leftrightarrow 2 x-y=1$$ and, $$\frac{x+1}{y}=1 \Leftrightarrow x-y=-1$$ Solving (i) and (ii), we get : $x=2, y=3$. Hence, the required fraction is $\frac{2}{3}$.
Explanation as extracted from the printed page; notation may be imperfect.