ABC26GN1899 · Surds and Indices

Subject: General Aptitude · Chapter: Surds and Indices · Exam: 2009 · Marks: · Difficulty:

$\frac{16 \times 32}{9 \times 27 \times 81}=$ ?
(a)$\left(\frac{2}{3}\right)^{9}$
(b)$\left(\frac{2}{3}\right)^{11}$
(c)$\left(\frac{2}{3}\right)^{12}$
(d)$\left(\frac{2}{3}\right)^{13}$
Answer
Answer (as printed): A
Explanation
$\frac{16 \times 32}{9 \times 27 \times 81}=\frac{2^{4} \times 2^{5}}{3^{2} \times 3^{3} \times 3^{4}}=\frac{2^{(4+5)}}{3^{(2+3+4)}}=\frac{2^{9}}{3^{9}}=\left(\frac{2}{3}\right)^{9}$.

Explanation as extracted from the printed page; notation may be imperfect.

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