ABC26GN1904 · Surds and Indices

Subject: General Aptitude · Chapter: Surds and Indices · Exam: 2008 · Marks: · Difficulty:

$(10)^{24} \times(10)^{21-}=$ ?

(a)3

(b)10

(c)100

(d)1000

Answer

Answer (as printed): D

Explanation

$(10)^{24} \times(10)^{21-}=10^{(24-21)}=10^{3}=1000$.

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