(i) We know that $\log_{a}1=0$, so $\log_{7}1=0$. (ii) We know that $\log_{a}a=1$, so $\log_{34}34=1$. (iii) We know that $a^{\log_{a}x}=x$. Now, $36^{\log_{6}4}=6^{2(\log_{6}4)}=6^{\log_{6}(4^{2})}=6^{\log_{6}16}=16$.
Explanation as extracted from the printed page; notation may be imperfect.