ABC26GN2033 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

The value of $\log _{2 \sqrt{3}}$ (1728) is
(a)3
(b)5
(c)6
(d)9
Answer
Answer (as printed): C
Explanation
Let $\log _{2 \sqrt{3}}(1728)=x$. Then, $(2 \sqrt{3})^{x}=1728=(12)^{3}=\left[(2 \sqrt{3})^{2}\right]^{3}=(2 \sqrt{3})^{6}$. $\therefore x=6$, i.e., $\log _{2 \sqrt{3}}(1728)=6$.

Explanation as extracted from the printed page; notation may be imperfect.

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