ABC26GN2070 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

The value of $16^{\log 45}$ is
(a)$\frac{5}{64}$
(b)5
(c)16
(d)25
Answer
Answer (as printed): D
Explanation
We know that : $a^{\log _{a} x}=x$. $$\therefore 16^{\log _{4} 5}=\left(4^{2}\right)^{\log _{4} 5}=4^{2 \log _{4} 5}=4^{\log _{4}\left(5^{2}\right)}=4^{\log _{4} 25}=25 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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