ABC26GN2096 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: 2009 · Marks: · Difficulty:

If $\log 2=0.30103$, the number of digits in $4^{50}$ is
(a)30
(b)31
(c)100
(d)200
Answer
Answer (as printed): B
Explanation
$\log 4^{50}=50 \log 4=50 \log 2^{2}=(50 \times 2) \log 2=100 \times \log$ $2=(100 \times 0.30103)=30.103$. ∴ Characteristic $=30$. Hence, the number of digits in $4^{50}=31$.

Explanation as extracted from the printed page; notation may be imperfect.

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