ABC26GN2105 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: · Marks: · Difficulty:
Evaluate: (Bank P.O., 2009) (i) 70\% of 320 + 45\% of 240 (ii) $16 \frac{2}{3} \%$ of 600 gm $-33 \frac{1}{3} \%$ of 180 gm
Answer
Explanation
(i) 70\% of 320 + 45\% of $240=\left(\frac{70}{100} \times 320+\frac{45}{100} \times 240\right)=224+108=332$. (ii) $16 \frac{2}{3} \%$ of $600 \mathrm{gm}-33 \frac{1}{3} \%$ of 180 gm $$=\left[\left(\frac{50}{3} \times \frac{1}{100} \times 600\right)-\left(\frac{100}{3} \times \frac{1}{100} \times 180\right)\right] \mathrm{gm}=(100-60) \mathrm{gm}=40 \mathrm{gm} .$$
Explanation as extracted from the printed page; notation may be imperfect.
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