ABC26GN2212 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: 2006 · Marks: · Difficulty:
23\% of 8040 + 42\% of 545 $=?$ \% of 3000 (Bank P.O., 2006)
(a)56.17
(b)63.54
(c)69.27
(d)71.04
(e)None of these
Answer
Explanation
Let 23\% of 8040 + 42\% of $545=x \%$ of 3000. Then, $$\begin{aligned} & \left(\frac{23}{100} \times 8040\right)+\left(\frac{42}{100} \times 545\right)=\left(\frac{x}{100} \times 3000\right) \\ & \Rightarrow 30 x=1849.2+228.9=2078.1 \\ & \Rightarrow x=\frac{2078.1}{30}=69.27 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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