ABC26GN2422 · Percentage
Subject: General Aptitude · Chapter: Percentage · Exam: 2006 · Marks: · Difficulty:
The population of a town is $4.2 \times 10^{6}$. If the population increases by 75 per 1000 per annum, then what will be the population after 2 years?
(a)4633628
(b)4853625
(c)5253495
(d)5853615
Answer
Explanation
Percentage annual increase $=\left(\frac{75}{1000} \times 100\right) \%=7 \frac{1}{2} \%=\frac{15}{2} \%$. $$\begin{aligned} \text { Population after 2 years } & =4200000\left(1+\frac{15}{2 \times 100}\right)^{2} \\ & =\left(4200000 \times \frac{43}{40} \times \frac{43}{40}\right)=4853625 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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