ABC26GN2705 · Profit and Loss
Subject: General Aptitude · Chapter: Profit and Loss · Exam: 2006 · Marks: · Difficulty:
A shopkeeper cheats to the extent of $10 \%$ while buying as well as selling, by using false weights. His total gain is
(a)10\%
(b)11\%
(c)20\%
(d)21\%
(e)$22 \frac{2}{9} \%$
Answer
Explanation
Rule: Gain $\%=\frac{(100+\text { common gain } \%)^{2}}{100}-100$. $$\begin{aligned} \therefore \text { Gain } \% & =\left[\frac{(100+10)^{2}}{100}-100\right] \% \\ & =\left(\frac{12100-10000}{100}\right) \%=21 \% . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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